Question

In rhombus ABCD, diagonal BD= 6" and diagonal AC-8".
The sides of the rhombus are

Answer 1

Answer: 5

Step-by-step explanation:

Let the point where the diagonals intersect be point E.

Since the diagonals of a rhombus are perpendicular bisectors of each other, this means that:

• BE = 3
• AE = 4
• AEB is a right triangle

So, using the Pythagorean theorem,

$3^{2}+4^{2}=(AB)^{2}\\\\25=(AB)^{2}\\\\AB=5$

So, each side of the rhombus has a length of 5.