Question

Which of the following is the center and radius of the circle?

x2 + y2 + 4x – 14y + 46 = 0

Center (2, –7); r = 7
Center (–4, 14); r equals square root 46
Center (4, –14); r = 46
Center (–2, 7); r equals square root 7

Answer 1

The centre of the circle is (-2,7) and the radius is √7 ,  Option D is the right answer.

What is the standard equation of a Circle ?

The standard equation of a Circle is

(x-h)² +(y-k)² = r²

where h and k is the centre of the circle , r is the radius

The given equation is

x² + y² + 4x – 14y + 46 = 0

x² +4x +4 -4 +y² -2.7y + 49-49+46 = 0

(x + 2)² + (y-7)² -4-49+46 = 0

(x + 2)² + (y-7)²= 7

Therefore the centre of the circle is (-2,7) and the radius is √7 ,

Therefore Option D is the right answer.

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