Question

How many atoms of scandium are in
75.0 g? (Sc, 44.96 g/mol)
75.0 g
1 mole Sc
6.02×1023 atom
44.96 g Sc
1 mole Sc

[?] x 10⁰ atoms Sc

Answer 1

10.045830 × $10^{23}$ atoms of scandium are in 75.0 g.

What are moles?

A mole is defined as 6.02214076 × $10^{23}$ of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

Mass of  scandium = 7

Molar mass of scandium=44.96 g/mol

$Moles = \frac{mass}{molar \;mass}$

$Moles = \frac{75.0 g}{44.96 g/mol}$

Moles =1.66814 moles

Number of atom=  1.66814 moles x 6.02214076 × $10^{23}$

Hence, 10.045830 × $10^{23}$ atoms of scandium are in 75.0 g.

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Answer 2

The number of Scandium atoms in 75 g will be 10²⁴ atoms.

How to find number of atoms ?

To calculate the number of atoms in a sample, divide its weight in grams by the amu atomic mass from the periodic table, then multiply the result by Avogadro's number : 6.02 x 10²³

Formula used;

Number of atoms = Given weight / Atomic weight x 6.023 x 10²³

                             = 75 / 44.96 x 6.023 x 10²³

                             

                             = 10²⁴ atoms.

Hence, The number of Scandium atoms present in 75 g will be 10²⁴ atoms.

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