Question

A pitcher throws a softball toward home
plate. When the ball hits the catcher's mitt, its
horizontal velocity is 32 meters/second. The
softball's velocity goes to 0 meters/second in
0.8 seconds when caught. If the softball has
a mass of 0.2 kilograms, what's the force of
the impact? Use F= ma, where

Answer 1

The force of impact given that the ball was caught for 0.8 s is – 8 N

Data obtained from the question

• Initial velocity (u) = 32 m/s
• Final velocity (v) = 0 m/s
• Mass (m) = 0.2 Kg
• Time (t) = 0.8 s
• Force (F) = ?

How to determine the force

F = m(v – u) / t

F = 0.2(0 – 32) / 0.8

F = (0.2 × – 32) / 0.8

F = – 8 N

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