Question

In a population of white and brown rats, 16% of the population is white. if white hair is recessive to brown, what frequency of individuals have a homozygous dominant genotype?

Answer 1

0.36

Explanation:

For the recessive trait to show in the phenotype, the individual has to be homozygous recessive for the gene. Therefore if we designate the allele for White color as r and that of Brown as R;

rr = 16% = 0.16   → This is the gene frequency for recessive population

To find the allele frequency

√0.16

= 0.4

Remember the hardy Weinberg principle of allele; All allelic frequency of a gene adds up to 1 in an ideal population (that observes certain assumptions).

p + q = 1

p + 0.4 = 1

p = 1 – 0.4

p = 0.6

The allelic frequency of Brown hair is 0.6.

The frequency of individuals of a homozygous dominant genotype will be;

P² + 2pq + q² = 1

0.6 * 0.6 = 0.36

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