Question

A plastic container holds 3 red balls, 2 green balls, and 3 yellow balls. What is the probability of choosing a green ball, replacing it, and then choosing a yellow ball?

Answer 1

Answer:

$0.09375$

Step-by-step explanation:

the total number of balls = 3 + 3 + 2 = 8

Let p be the probability of choosing a green ball, replacing it, and then choosing a yellow ball.

$p=p\left( \text{choosing a green ball} \right) +p\left( \text{choosing a yellow ball} \right)$

  $=\frac{2}{8} \times \frac{3}{8}$

  $=\frac{6}{64}$

  $= 0.09375$