Question

What is the value of "a" in the following quadratic? (Make sure the equation is in
standard form: ax² + bx+c=0)
x^2 + 28 = -11x

Answer 1

Answer: a= - $\frac{b}{x}$- $\frac{c}{x2}$

Step-by-step explanation:

1. Move all terms not containing $\alpha$ to the right side of the equation.

$\alpha$$x^{2}$=-bx-c

2. Divide each term in $\alpha x^{2}$=-bx-c by $x^{2}$ and simplify.

a= - $\frac{b}{x}$ - $\frac{c}{x^{2} }$