Question

help please!
will give brainliest to the correct answer.

question; the work one by friction force to stop a car of mass 1000 kg moves with velocity 72km/h is ..........

a) 72 x 10³ J

b) 2 x 10⁴ J

c) 2 x 10⁵ J

d) 4 x 10⁵ J
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an explanation for future reference would be appreciated^^​

Answer 1

Answer:

b)

Explanation:

The work done by friction is equal to the all of the initial Kinetic Energy lost when the vehicle comes to a complete stop

KE = 1/2 m v^2

       72 km / hr = 20 m/s

 KE = 1/2  *  1000 kg  * (20 m/s)^2  = 200 000 J = 2 x 10^4 J