The number of particles of 285 grams of aluminum oxide (Al2O3) is 1.68 x 10²⁴ particles.
Number of moles of the Al2O3
The number of moles of the given aluminum oxide is calculated as follows;
Al2O3 = 101.96 g/mol
moles = 285/101.96
moles = 2.795 moles
1 mole = 6.02 x 10²³ particles
2.795 moles = ?
= 2.795 x 6.02 x 10²³ particles
= 1.68 x 10²⁴ particles.
Thus, the number of particles of 285 grams of aluminum oxide (Al2O3) is 1.68 x 10²⁴ particles.
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