The moles of phosphorous which are present in 750 grams of phosphorous is 24.27 moles.
Relation between the mass and moles of any substance will be represented as:
Moles of phosphorous which are present in 750 grams will be calculated as:
n = 750g / 30.9g/mol = 24.27 moles
Hence the resultant moles of phosphorous is 24.27 moles.
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