Answer: C is the correct answer.The approximate stopping distance of the car =239 feet.
Step-by-step explanation:
Given: A car’s stopping distance in feet is modeled by the equation
[tex]d(v)=2.15\frac{v^2}{58.4f}[/tex] where v is the initial velocity of the car in miles per hour and f is a constant related to friction.
If the initial velocity of the car v= 47 mph and f = 0.34 then
The distance of the car [tex]d(47)=2.15\frac{{47}^2}{58.4\times0.34}=2.15\frac{2209}{19.856}=2.15\times111.25=239.18[/tex]
≈239 feet [ round to nearest ones]
Therefore ,the approximate stopping distance of the car =239 feet.
