Question

Some electronic devices operate on a DC voltage of 7.5 V. To obtain 7.5 V DC from a 120-V (rms) AC line, first the voltage is dropped to 7.5 V (rms) AC by a transformer, and then the 7.5 V AC is converted to 7.5 V DC by a rectifier circuit involving diodes. Consider a device of resistance 15 Ω connected to the 7.5-V DC output of the rectifier. Assuming no power loss anywhere, what is the rms current, in amperes, in the secondary winding? Again assuming no power loss anywhere, what is the rms current, in milliamperes, in the primary winding?

Answer 1

The rms current, in amperes, in the secondary winding is 0.5 A and the rms current, in milliamperes, in the primary winding is 31.25 mA.

Output current

The rms current, in amperes, in the secondary winding is calculated as follows;

V = IR

I = V/R

I = 7.5 / 15

I = 0.5 A

Input current

The rms current, in milliamperes, in the primary winding is calculated as follows;

$\frac{I_p}{I_s} = \frac{V_s}{V_p} \\\\I_p = \frac{V_sI_s}{V_p}\\\\I_p = \frac{7.5 \times 0.5}{120} \\\\I_p = 0.03125\\\\I_p = 31.25 \ mA$

Thus, the rms current, in amperes, in the secondary winding is 0.5 A and the rms current, in milliamperes, in the primary winding is 31.25 mA.

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