Question

Calculate the number of moles of water produced when 3.3 mol of cu(NO3)2 are
formed in the reaction

Answer 1

3 Cu(s) + 8 HNO3(aq) = 3 Cu(NO3)2(s) + 2NO(g) + 4H2O(l)

3 moles Cu(NO3)2 ------------------ 4 moles H2O
3.3 moles Cu(NO3)2 --------------- ( moles H2O)

moles H2O = 3.3 x 4 / 3

moles H2O = 13.2 / 3

= 4.4 moles of H2O

hope this helps!