Question

A uniform electric field of magnitude 31 V/m makes an angle of 30∘

with a displacement of length 10 m.

1)

What is the potential difference of the final position relative to the initial position of this displacement? (Express your answer to two significant figures.)

Answer 1

We are given with
electric field strength of 31 V/m
the displacement is 10 m
angle of 30 degrees

The  potential difference of the final position relative to the initial position of this displacement is
31 (10) sin 30
= 155 V

The potential difference is 155 V.