Question

A tight rope walker falls from the tight rope and it’s a safety net. It take .25 seconds for her to stop moving. The net provided an impulse of 250 n*s of force. What was the force that the tight rope walker hit the net.

dam.n bored ~​

Answer 1

Hey there mate :)

Given:-

Time: 0.25s

Impulse: 250 n*s

Procedure:-

As Impulse=Force×Time

$i = f \times t$

$= > f = \frac{i}{t}$

$= > f = \frac{250N \times s}{0.25s}$

$= > 1000N$

So, the force would be 1000 N

Answer 2

The force that the tight rope walker hit the net is 1,000 N.

Net impulse on the walker

The net impulse on the rope walker is given as 250 Ns. The force that the tight rope walker will hit the net will be determined using this impulse.

Force of the walker

The force that the tight rope walker hit the net is calculated by applying Newton's second law of motion as follows;

$F = \frac{J}{t}$

where;

• J is the impulse = 250 Ns
• t is the time of motion = 0.25 s

$F = \frac{250}{0.25} \\\\F = 1000 \ N$

Learn more about impulse here: https://brainly.com/question/25700778