Question

A sample 0.5 mole sample of NO2 gas occupies a 0.620 L container at 25 °C. What is the pressure of this gas?

Answer 1

The pressure of the sample of the gas in the container at 25 °C occupying 0.62 L is 19.73 atm

Data obtained from the question

• Volume (V) = 0.62 L
• Temperature (T) = 25 °C = 25 + 273 = 298 K
• Gas constant (R) = 0.0821 atm.L/Kmol
• Number of mole (n) = 0.5 mole

• Pressure (P) = ?

Using the ideal gas equation, the pressure of the gas can be obtained as follow:

PV = nRT

Divide both side by V

P = nRT / V

P = (0.5 × 0.0821 × 298) / 0.62

P = 19.73 atm

Thus, the pressure of the gas is 19.73 atm

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