Question

The flight of a javelin released six. 5 feet from the ground at an initial velocity of 68 ft./s is modeled by the function age equals 16 t^2+68t+6.5 where H is the height of the Javelin in feet after t seconds. When will the javelin hit the ground? Round to the nearest hundredth if necessary

Answer 1

The equation of the javelin path h(t) = -16t^2+68t+6.5 is a quadratic function

The javelin hits the ground after 4.344 seconds

How to determine when the javelin hits the ground?

The equation of the javelin path is given as:

h(t) = -16t^2+68t+6.5

When it hits the ground, h(t) = 0.

So, we have:

-16t^2+68t+6.5 = 0

Using a graphing calculator, we have:

t = 4.344 and t = -0.094

Time cannot be negative.

So, we have:

t = 4.344

Hence, the javelin hits the ground after 4.344 seconds

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