Question

A boy swings a 30 g fishing sinker around his head attached to his fishing line. The radius ofthe circular motion of the sinker is 65 cm. The sinker does 2 revolutions per second.
(a) What is the period of rotation of the sinker?
(b) What is the tangential velocity of the sinker?
(c) Calculate the acceleration of the sinker.

Answer 1

Explanation:

a) Peroid = 1/frequency

F = 2 rev. per second = 2Hz

period = 1/2 = 0.5s

b) Tangential velocity(Vt) = ωr, where ω is thr angular velocity(2 * Pi(3.142) * f(frequency)) and r is the radius

Therefore; Vt = 2 * 3.142 * 2 * 0.65(65/100)

= 8.1692

= 8.2m/s

c) a = (V^2)/r where V is the velocity and r is the radius

a = (8.2^2)/0.65

a = 103m/s^2