Question

Calculate the amount of heat liberated (in kJ) from 575g of diamond when it cools from 87.1 degrees Celsius to 22.9 degrees Celsius. The specific heat is 0.502 J/g•degrees Celsius

Answer 1

The amount of heat liberated is -18.53 kJ

Amount of heat liberated

The amount of heat liberated by the diamond is given by Q = mc(T' - T) where

• m = mass of diamond = 575 g,
• c = specific heat of diamond = 0.502 J/g-°C,
• T = initial temperature of diamond = 87.1 °C and
• T' = final temperature of diamond = 22.9 °C.

Substituting the values of the variables into the equation, we have

Q = mc(T' - T)

Q = 575 g × 0.502 J/g-°C × (22.9 °C - 87.1 °C)

Q = 575 g × 0.502 J/g-°C × (-64.2 °C)

Q = 575 g × (-32.2284 J/g)

Q = -18531.33 J

Q = -18.53133 kJ

Q ≅ -18.53 kJ

So, the amount of heat liberated is -18.53 kJ

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