Question

N2(g) + 3H2(g) →2NH3(g)
At the end of the chemical reaction, 5 moles of NH3 are produced.
How many moles of N2 and H2 entered the reaction?

Answer 1

Answer:

2.5 moles of N₂ and 7.5 moles of H₂ entered the reaction

Explanation:

In reaction:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

You can see that the stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) requires the following amounts of reagents and are produced:

• N₂: 1 mole
• H₂: 3 moles
• NH₃: 2 moles

The following three rules can apply:

• If 2 moles of NH₃ are produced from 1 mole of N₂ by stoichiometry of the reaction, 5 moles of NH₃ from how many moles of N₂ are produced?

$moles of N_{2} =\frac{5 moles of NH_{3} *1 mole of N_{2} }{2 moles of NH_{3}}$

moles of N₂= 2.5

• If 2 moles of NH₃ are produced from 3 moles of H₂ by stoichiometry of the reaction, 5 moles of NH₃ from how many moles of H₂ are produced?

$moles of H_{2} =\frac{5 moles of NH_{3} *3 mole of H_{2} }{2 moles of NH_{3}}$

moles of H₂= 7.5

2.5 moles of N₂ and 7.5 moles of H₂ entered the reaction