Question

The graph displays a linear function.

Answer 1

Answer:

$y = -\frac{2}{3}x +0$  OR $y = -\frac{2}{3}x$

Step-by-step explanation:

First, find the slope (m) using two points (0,0) and (-6, 4)

m = $\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{4-0}{-6-0} \\\\m=\frac{4}{-6}\\\\m=\frac{2}{-3}\\\\m=-\frac{2}{3}$

$y=mx+b$

$y = -\frac{2}{3}x +b$

Now, we find b using (-6, 4)

$y = -\frac{2}{3}x +b$

$4 = -\frac{2}{3}(-6) +b\\\\4 = \frac{12}{3} +b\\\\4 = 4 +b\\\\-4 -4\\\\0=b$

$y = -\frac{2}{3}x +0$  OR $y = -\frac{2}{3}x$

Hope this helps!