Question

PLS HELP IM ABOUT TO BURN MY SCHOOL, jk BUT I STILL NEED HELP

Answer 1

Hey there!

Plug in the values and solve:

$\bold{\displaystyle\frac{2x^2+y^2}{3} }$

We're given that

x=1.5

y=3

Solve

${\displaystyle\frac{2(1.5)^2+(3)^2}{3} }$

$\displaystyle\frac{2(1.5)^2+9}{3}$

$\displaystyle\frac{2*2.25+9}{3}$

$\displaystyle\frac{4.5+9}{3}$

$\displaystyle\frac{13.5}{3}$ (as an improper fraction)

4.5 (As a decimal)

Hope everything is clear.

Let me know if you have any questions!

#KeepLearning

$\bold{A~felicitous~teenager~here}$