Question

A student obtained a test tube with a suspension of white, slightly soluble calcium hydroxide in water. This system was at equilibrium as represented by the following equation:_______.
Ca(OH)2(s)Ca2(aq)+ 20H(aq)
Write the equilibrium constant expression for this reaction.

Answer 1

Answer:

K = [Ca²⁺] [OH¯]² / [Ca(OH)₂]

Explanation:

Equation for the reaction is given below:

Ca(OH)₂(s) —> Ca²⁺(aq) + 2OH¯(aq)

Equilibrium constant =?

Equilibrium constant (K) for a reaction is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

Thus, we can write the equilibrium constant (K) for the above reaction as follow:

Ca(OH)₂(s) —> Ca²⁺(aq) + 2OH¯(aq)

K = [Ca²⁺] [OH¯]² / [Ca(OH)₂]