Question

2. In square MISA, the diagonals intersect at point P. If m_MPA

= (2s + 3t)º, MZISP = (4r + s)° and m_MIS = (3s – 2t)º, find

the values of r, s, and t.

Answer 1

The diagonal of the square MISA bisect the angle at the vertices

The values of r, s and t are r  = 2.6, s = 34.6 and t = 6.9

How to determine the values of r, s and t?

The given parameters are:

MPA = (2s + 3t)º

ISP = (4r + s)°

MIS = (3s – 2t)º

The angle between the diagonal of a square is 90 degrees.

So, we have:

2s + 3t = 90

Multiply by 2

4s + 6t = 180

The angle at the vertices of the square is 90 degrees.

So, we have:

3s - 2t = 90

Multiply by 3

9s - 6t = 270

The diagonal bisect the angle at the vertex.

So, we have:

4r + s = 45

Rewrite the equations

4s + 6t = 180

9s - 6t = 270

4r + s = 45

Add the first and the second equations

4s + 9s + 6t - 6t = 180 + 270

13s= 450

Divide by 13

s = 34.6

Substitute s= 34.6 in 4r + s = 45 and 3s - 2t = 90

4r + 34.6 = 45

Solve for r

r  = 2.6

3 * 34.6 - 2t = 90

Solve for t

t = 6.9

Hence, the values of r, s and t are r  = 2.6, s = 34.6 and t = 6.9

Read more about squares at:

https://brainly.com/question/24487155