Question

Find the equation of a line that passes through the point (4,2) and has a gradient of -2. Leave your answer in the form y=mx+c​

Answer 1

Answer:

y = - 2x + 10

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - 2 , then

y = - 2x + c

to find c substitute (4, 2 ) into the equation

2 = - 8 + c ⇒ c = 2 + 8 = 10

y = - 2x + 10 ← equation of line

Answer 2

Answer:

y = - 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - 2 , then

y = - 2x + c

To find c we must substitute (4, 2 ) into the equation

2 = - 8 + c, c = 2 + 8 = 10

y = - 2x + 10