Question

Executives for a car dealership are interested in the sales for the type of vehicle, SUV or truck, and the type of power train, two-wheel drive (2WD), four-wheel drive (4WD), or all-wheel drive (AWD). The data from the
sales of 165 vehicles are displayed in the two-way table.
A vehicle is randomly selected. Let S be the event that
the vehicle is an SUV and let D be the event that the vehicle has 4WD. What is the value of P(S and Dc)?
O 0.04
O 0.23
O 0.38
O 0.41

Answer 1

Assuming S is the event that the vehicle is an SUV the value of P(S and D) is:0.38.

Probability

Number of vehicles=165

Total number of SUV=10+23+52=85

Hence:

The event that vehicle is SUV(S)=85

The event that vehicle is 4WD(D)=23

Value of P(S and D)=85-23/165

Value of P(S and D)=62/165

Value of P(S and D)=0.375

Value of P(S and D)=0.38 (Approximately)

Inconclusion the value of P(S and D) is:0.38.

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Answer 2

Answer:

c) 0.38

Step-by-step explanation:

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