Question

How do these results about area and perimeter of similar quadrilaterals compare with similar situations for triangles?

Answer 1

Answer:

Let's see

Step-by-step explanation:

Two triangles are same ∆1 and ∆2

They have same height and breath

Now ∆1= ∆2

=> ar(∆1)= ar(∆2)

The same is for quadrilaterals

Answer 2

the ratio of the perimeters of similar figures is equal to their scale factor and that the ratio of their areas is equal to the square of their scale factor.