Answer: slope of a line perpendicular is [tex]\frac{5}{7}[/tex]; slope of a line parallel to this line is [tex]-\frac{7}{5}[/tex].
Step-by-step explanation:
Rewrite the line in y = mx + b form, where m is slope and b is y-intercept.
7x + 5y = -2
5y = -7x -2
y = [tex]-\frac{7}{5}[/tex]x - [tex]\frac{2}{5}[/tex]
The product of two slope of perpendicular line is -1.
Let x be the other line that perpendicular line with the line 7x + 5y = -2.
（[tex]-\frac{7}{5}[/tex])x = -1
x = [tex]\frac{5}{7}[/tex]
The slope of a line parallel to this line is the same, which is [tex]-\frac{7}{5}[/tex].
