Question

$6+\sqrt[5]{249-2x} =7$

Answer 1

Answer: 124

Step-by-step explanation:

First, subtract 6 on both sides to get:

$\sqrt[5]{249-2x} =1$

Take both sides to the 5th power. The radical will cancel, and the right side will be unchanged:

$249-2x=1$

Subtract 249 on both sides:

$-2x=-248$

$2x=248$

$x=124$

Answer 2

Answer:

x=124

Step-by-step explanation:

$6+\sqrt[5]{249-2x} =7\\\sqrt[5]{249-2x} =7-6=1\\249-2x=1^5=1\\249-1=2x\\2x=248\\x=\frac{248}{2} =124$