Question

A transformer with 80 turns in its primary coil and 20 turns in its secondary , if it is 65% efficient and connected to an input of 1000 V find the following if the current in the primary is 40 mA

Answer 1

The secondary voltage is 250 V and the secondary current is 2 A.

General transformer equation

The general equation for an ideal transformer is given as;

$\frac{N_s}{N_p} = \frac{V_s}{V_p} = \frac{I_p}{I_s}$

where;

• Vs is output voltage or secondary voltage
• Vp is input voltage
• Is is output current
• Ip is the input current
• Ns is secondary turns
• Np is primary turns

Output voltage of the transformer

The output voltage of the transformer is calculated as follows;

$\frac{N_s}{N_p} = \frac{V_s}{V_p} \\\\\frac{20}{80} = \frac{V_s}{1000} \\\\80V_s = 20,000\\\\V_s = 250 \ V$

Secondary current or output current

The secondary current in the transformer is calculated as follows;

$\frac{N_s}{N_p} = \frac{I_p}{I_s} \\\\\frac{20}{1000} = \frac{0.04}{I_s} \\\\I_s = \frac{1000 \times 0.04 }{20} \\\\I_s = 2 \ A$

Thus, the secondary voltage is 250 V and the secondary current is 2 A.

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