is mathematically given as
RH=37.04%
Question Parameters:
the relative humidity of the air was 96% on a cold morning
when the temperature was 20 degrees celsius. In the afternoon
the air temperature has risen to 35 degrees celsius
Generally, the equation for the Relative humidity is mathematically given as
[tex]H=\frac{vapor pressure of water}{saturated vapor pressure of water}[/tex]
Therefore
At 20
where
vapor pressure of water at 20 =2.34kpa
[tex]H=\frac{96*2.34}{100}[/tex]
At 35
'vapor pressure of water at 20 =5.63kpa
H=\frac{96*5.36}{100}
In conclusion The relative humidity
RH=(90*2.34)/(100*5.63)*100
RH=37.04%
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