Question

SOMEONE HELP ME
Convert $25^{0}$ C to Fahrenheit.

Answer 1

Question:-

Convert 25° Celsius to Fahrenheit.

Answer:-

77° F

Explanation:-

The formula to convert Celsius to Fahrenheit is :-

$\tt {F \: = {C \times ( \frac{9}{5} ) + 32}}$

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Given, C = 25

=> F = 25 × (9/5) + 32

=> F = 45 + 32

=> F = 77

Answer 2

Answer:

$\boxed{\tt 25{}^{\circ} C = 7 7 {}^{ \circ} F}$

Explanation:

Question:

To Convert 25°C to Fahrenheit scale

Here, °C means Celsius

Given:

The value of Celsius, i.e. 25

Solution:

In relation

$\boxed{ \rightarrow \tt \cfrac{{}^{\circ}C }{5} = \cfrac{ {}^\circ F-32}{9}}$

Now put the value of Celsius: [25]

$\tt \implies \cfrac{25}{5} = \cfrac{ F-32}{9}$

Now Find the value of F. That would be the Fahrenheit.

Steps:

Cross Multiply:

$\tt \implies25 \times 9 = 5(F-32)$

Simplify the LHS and apply Distributive property for RHS:

$\tt \implies225 = 5 \: F - 160$

Flip this equation:

$\tt \implies5 F - 160 = 225$

Add 160 to both sides:

$\tt \implies5 F - 160 + 160 = 225 + 160$

Simplify:

$\tt \implies5 F - 0 = 385$

$\tt \implies \: 5 F = 385$

Divide both sides by 5:

$\tt \implies \cfrac{5F}{5} = \cfrac{385}{5}$

Use Cancellation method to cancel LHS and RHS:

$\tt \implies \cfrac{ {}^{1} {}^{} \cancel{5}F}{ {}^{1} \cancel5} = \cfrac{ {}^{77} \cancel{385}}{ {}^{1} \cancel5}$

$\tt \implies1F = 77$

$\boxed{\tt \implies{ {}^{ \circ} F} = 77}$

Hence, 25°C is equal to 77°F .

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