A square can be identified(characterized) by its diagonal. The minimum amount of fencing needed by Colton for given context is: Option C: 96 ft
Since fencing is done all around the square garden, it must be at least of the length of the sum of all 4 sides of the garden. This quantity is actually called the perimeter of the square.
Suppose that a square has side length 'a' units.
Then we get:
Diagonal of that square = [tex]a\sqrt{2}[/tex] units
Perimeter of that square = sum of all sides' lengths = a + a + a + a = 4a
For the given case, it is given that the square garden has got the length of its diagonal to be of 34 ft.
Thus, if we suppose that the garden has its side length = 'a' feet, then
Diagonal is [tex]a\sqrt{2}[/tex] feet
Thus,as both quantities of diagonals are same, thus,
[tex]a\sqrt{2} = 34\\\\a = \dfrac{34}{\sqrt{2}} \approx 24.042 \: \rm feet[/tex]
Thus, the minimum amount of fencing for this garden = its perimeter = 4a
= 4 times 24.042 = 96.168 ≈ 96 feet
Thus, The minimum amount of fencing needed by Colton for given context is: Option C: 96 ft
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