Respuesta :

Answer:

• From avogadro's number:

[tex]{ \tt{6.02 \times {10}^{23} \: atoms = 1 \: mole}} \\ { \tt{7.89 \times {10}^{28} \: atoms = (\frac{7.89 \times {10}^{28} }{6.02 \times {10}^{23} } )}} \\ \\ = { \tt{1.31 \times {10}^{5} \: moles }}[/tex]

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