The mass in units of g, of Br-79 in 16 g of CaBr₂ is 12.77 g
Determination of the mass of 1 mole of CaBr₂
1 mole of CaBr₂ = 40 + 2(78.92)
1 mole of CaBr₂ = 197.84 g
Determination of the mass of Br in 1 mole of CaBr₂
1 mole of CaBr₂ = 2Br = 2 × 78.92
1 mole of CaBr₂ = 157.84 g of Br
How to determine the mass of Br in 16 g of CaBr₂
197.84 g of CaBr₂ = 157.84 g of Br
Therefore,
16 g of CaBr₂ = (16 × 157.84) / 197.84
16 g of CaBr₂ = 12.77 g of Br
Thus, 16 g of CaBr₂ contains 12.77 g of Br
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