What are the oxidation numbers of the atoms in this reaction? Check all that apply. CH4(g) 2O2(g) → CO2(g) 2H2O(g) -4 for C in CH4 4 for C in CO2 -2 for O in all substances 1 for H in both CH4 and H2O 4 for O in H2O.

Respuesta :

-4 for C in [tex]\rm (CH_{4})[/tex] +4 for C in [tex]\rm CO_{2}[/tex] +1 for H in both [tex]\rm CH_{4}[/tex] and [tex]\rm H_{2}O[/tex] are the oxidation numbers.

Oxidation numbers are the digits that indicate the number of electrons lost, gained, or shared so that a chemical bond is created with atom or atoms.

How to know the oxidation numbers?

In methane, [tex]\rm (CH_{4})[/tex] carbon donates four electrons as it is more electronegative than hydrogen and hence will have an oxidation state of -4.

The oxidation state of the carbon in [tex]\rm CO_{2}[/tex] will be +4 as oxygen is more electronegative than the carbon and will donate an electron.

The oxidation state of the hydrogen will be +1 in both methane and water as the electronegativity of the hydrogen is smaller than both oxygen and carbon.

Therefore, options 1, 2 and 4 are correct.

Learn more about the oxidation state here:

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