Question

The density of benzene at 15 ∘C is 0.8787 g/mL. Calculate the mass of 0.1200 L of benzene at this temperature.

Answer 1

The mass of 0.1200 L of benzene at 15° Celsius is 105.44 g.

FURTHER EXPLANATION

Density is a measure of how tightly packed the particles of a material are. The more tightly packed the particles, the greater the density and vice versa.  Density is also mostly defined as the amount of matter in a given volume or space. The amount of matter corresponds to its mass. Density is an intensive property of matter so it may be used to qualitatively identify an unknown substance.

To determine the mass of benzene, recall the definition of density:

$density = \frac{mass}{volume}$

Since the density and the volume of benzene are given, the mass can be calculated as follows:

$mass = density \times volume$

Before the given volume and density can be plugged into the equation, volume of benzene must first be converted to milliliters.

$0.1200 \ L \times \frac{1000 \ mL}{1 \ L} = \boxed {120 \ mL}$

Plugging into the equation for mass:

$mass = 0.8787 \frac{g}{mL} \times 120 \ mL\\\\\boxed {mass = 105.444 \ g}$

LEARN MORE

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Keywords:  density, unit conversion, benzene

Answer 2

The correct answer will be "105.5 g".

The given values are:

Volume,

V = 0.1200 L

   = $0.1200\times 1000$

   = $120 \ mL$

Density,

D = 0.8787 g/mL

As we know,

→ $Density=\frac{Mass}{Volume}$

or,

→ $Mass = Volume\times Density$

By substituting the values, we get

            $=120\times 08787$

            $= 105.5 \ g$

Thus the above is the correct answer.  

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