Question

9. A student wished to prepare ethylene gas by dehydration of ethanol at 140oC using sulfuric acid as the dehydrating agent. A low-boiling liquid was obtained instead of ethylene. What was the liquid, and how might the reaction conditions be changed to give ethylene

Answer 1

We have that the the liquid is

• C_2H_5OH (ethanol
• And at a condition of H_2SO4 as catalyst and temp 170

From the question we are told

• A student wished to prepare ethylene gas by dehydration of ethanol at 140oC using sulfuric acid as the dehydrating agent.
• A low-boiling liquid was obtained instead of ethylene.
• What was the liquid, and how might the reaction conditions be changed to give ethylene

Ethylene formation

Generally the equation is

2C_2H_5OH------CH3CH_2O-CH_2CH_3+H_20

Therefore

with ethanol at 140oC

The product is diethyl ethen

The reaction at 170 ethylene will give

C_2H_5OH-------CH_2=CH_2+H_2O( at a condition of H_2SO4 as catalyst and temp 170)

Therefore

The the liquid is

• C_2H_5OH (ethanol

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