Question

What is the sum of the infinite geometric series? Negative 3 minus three-halves minus three-fourths minus three-eighths minus three-sixteenths minus ellipsis Negative StartFraction 93 Over 16 EndFraction Negative StartFraction 3 Over 32 EndFraction –4 –6.

Answer 1

The sum of the given infinite geometric series is -6.

The given geometric series is,

$-3,-\dfrac{3}{2},-\dfrac{3}{4},......$

It is required to find the sum of infinite geometric series.

How to find the sum of the infinite geometric series?

The formula for sum of infinite geometric series is,

$S=\dfrac{a}{1-r}$

where a is the first term and r is the common ratio.

In the given series, the first term is -3 and the common ratio is $\dfrac{1}{2}$.

So, the sum of the series can be calculated as,

$S=\dfrac{a}{1-r}\\ S=\dfrac{-3}{\frac{1}{2}}\\ S=-3\times 2\\ S=-6$

Therefore, the sum of the given infinite geometric series is -6.

For more details about geometric series, refer to the link:

https://brainly.com/question/2501276

Answer 2

Answer:

-6

Step-by-step explanation:

for those on edg its letter (D)