Answer:
[tex]\boxed{\bf f(x) = 115}[/tex]
Step-by-step explanation:
Given polynomial function :-
[tex]f(x) = 10x + 45[/tex]
To find :-
[tex] \sf \: f(7)[/tex]
Solution:-
[tex]\sf \implies \: f(x) = 10x + 45[/tex]
Here, the value of x is 7(given).
So, Substitute the value of x on the RHS and on LHS :-
[tex]\sf \implies{f}(“7”) = 10(“7”) + 45[/tex]
Simplify the RHS:-
Multiply 10 and 7 :-
[tex]\sf \implies{f}(7) = 10 \times 7 + 45[/tex]
[tex]\sf \implies{f}(7) = 70 + 45[/tex]
Add 70 and 45 :-
[tex]\sf \implies{f}(7) = 115[/tex]
We're done!
Hence, the value of f(7) would be,
[tex]\sf \implies{f}(7) = 115[/tex]
[tex] \rule{225pt}{2pt}[/tex]
I hope this helps!
Let me know if you have any questions.