Question

Sheila weighs 60 kg and is riding a bike. Her momentum on the bike is 340 kg • m/s. The bike hits a rock, which stops it completely and throws Sheila forward onto the pavement. If there is no net force on the system, what is Sheila’s velocity immediately after she is thrown from the bike? 1. 8 m/s 2. 0 m/s 5. 0 m/s 5. 7 m/s.

Answer 1

The final velocity of sheila after the collision is about 5.7 m/s. Option D is correct.

What is conservation of momentum?

The total momentum of an object in an isolated system is conserved. It can be represented as;

$p_1 = p_2$

Where,

$p_1$ - momentum before the collision

$p_2$- momentum after the collision

Momentum before collision:

$p_1 = (m +M) v_1$

Where,

$m$  - mass of sheila

$M$- mass of bike

$v$ - velocity of sheila-bike system,

So,

$p_1$ = 340 \rm \ kgms

Momentum after the collision,

$P_2 = mv_2 + MV_2$

Where,

$MV_2$ -momentum of bike = 0 kgm/s

$mv_2$ - momentum of sheila

Since the bike stops after, the momentum of the bike will be zero,

$P_2 = 60 \times v_2$

From the conservation of momentum;

$340 = 60 \times v_2\\\\ v_2 = \dfrac {340 }{60}\\\\ v_2 = 5.66$

Therefore, the final velocity of sheila after the collision is about 5.7 m/s.

Learn more about the conservation of momentum;

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