Question

What is the trigonometric ratio for sin S

triangle Q R S with right angle R. Q S equals 68. R S equals 60.

Answer 1

Answer:

Trigonometric ratio for sin S = 0.471

Explanation:

 From figure we have sin S = QR/QS

 QS = 68

 By Pythagoras theorem we have,

    QS² = QR² + RS²

    68² = QR² + 60²

    QR² = 68² - 60²

    QR = 32

  sin S = QR/QS = 32/68 = 0.471

Trigonometric ratio for sin S = 0.471

Answer 2

By applying the sine trigonometry, the trigonometric ratio for sin S is equal to 8/17.

How to apply basic trigonometry.

In order to determine the trigonometric ratio for sin S, we would apply basic trigonometry. From the right-angled triangle shown in the image attached below, we can deduce the folloing parameters:

• Angle (θ) = 45°

• Adjacent (RS) = 60.

• Hypotenuse (QS) = 68.

Next, we would solve for the opposite side (QR) of the right-angled triangle by applying Pythagorean's theorem:

QR² = QS² - RS²

QR² = 68² - 60²

QR² = 4,624 - 3,600

QR² = 1024

QR = √1024

QR = 32 units.

Now, we would use the sine trigonometry to determine the trigonometric ratio for sin S as follows:

Sinθ = Opp/Hyp = QR/QS

Sinθ = 32/68

Sinθ = 8/17.

Read more on sine trigonometry here: https://brainly.com/question/20367642

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