Question

When a 0.22 kg air-track cart is attached to a spring, it oscillates with a period of 0.84 s. What is the force constant for this spring

Answer 1

Answer:

Explanation:

ω = 2π/Τ = √(k/m)

4π²/T² = k/m

k = 4π²m/T²

k = 4π²(0.22)/0.84²

k = 12.3090304...

k = 12 N/m