Question

In a physics investigation, students drop a steel ball with a mass of 0.567 grams from a fourth-story window into a large sand pit. The release point is 10.0 m above the ground. Assuming no air resistance, how much kinetic energy does the ball have when it is 3.00 m above the surface of the sand?

Answer 1

The kinetic energy of the ball above the surface of the sand is 0.0389 J.

The given parameters:

• Mass of the steel ball, m = 0.567 g
• Height from which the ball was released, h = 10 m
• Final position of the ball, = 3 m

The kinetic of the ball at the given final position of the ball is the change in the potential energy of the ball.

The kinetic energy of the ball above the surface of the sand is calculated as follows;

$K.E = \Delta P.E\\\\K.E = mgh_0 - mgh_f\\\\K.E = mg(h_o - h_f)\\\\K.E = 0.567 \times 10^{-3} \times 9.8(10 - 3)\\\\K.E = 0.0389 \ J$

Thus, the kinetic energy of the ball above the surface of the sand is 0.0389 J.

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