Question

A polynomial function has a root of –6 with multiplicity 3 and a root of 2 with multiplicity 4. If the function has a negative leading coefficient and is of odd degree, which could be the graph of the function?

i gave you 4 files they are the four options in order from a to b
please no files my computer will not let me view them
thank you!!!

Answer 1

Functions can be represented on graphs

The possible graph of the function is graph (a)

The roots and the multiplicities are given as:

Roots  Multiplicity

-6              3

2              4

Assume the variable is x.

The function (at this stage) can be represented as:

$f(x) = a(x + 6)^3(x - 2)^4$

The function has a negative leading coefficient.

This means that a < 1.

So, we have:

$f(x) = -a(x + 6)^3(x - 2)^4$

Hence, the possible graph of the function is graph (a)

Read more about graphs and functions at:

https://brainly.com/question/14323743

Answer 2

Answer:

A polynomial function can be represented on a graph

The given parameters are:

So, the equation is represented as:

This gives

The equation has a negative leading coefficient.

This means that, the value of a is less than 0 i.e. a < 0

Assume a = -2, the equation become

f(x)=-2(x+6)^3(x-2)^4

Step-by-step explanation: