Question

3. A body starts from rest and accelerates to a velocity of 5m's in 20s, it maintains this velocity for 10s and then deaccelerate to rest in further 10s.

Draw the velocity time graph for the motion.
Calculate the initial acceleration of the body and the total distance covered.​

Answer 1

Answer:

Explanation:

initial acceleration

a = Δv/t = (5 - 0) / 20 = 0.25 m/s²

distance covered during acceleration

d₁ = ½at² = ½(0.25)20² = 50 m

max velocity v = at = 0.25(20) = 5 m/s

distance covered at constant speed

d₂ = vt = 5(10) = 50 m

deceleration = Δv/t = (0 - 5) / 10 = -0.5 m/s²

distance covered during deceleration

d₃ = ½at² = ½(0.5)10² = 25 m

d = d₁ + d₂ + d₃ = 50 + 50 + 25 = 125 m