The biological Oxygen demand of the lake is increased by 1.5 ton.
Discussion:
The reaction of methanol with Oxygen is as follows;
- 2CH3OH + 3O2 ==> 2CO2 + 4H2O.
In the reaction above; Since Methanol, CH3OH and Oxygen, O2 have the same molar mass; 32.
Therefore we can say since;
2 moles of CH3OH requires 3 moles of O2.
Therefore, 1 ton of methanol will require 1.5 ton of oxygen.
The biological Oxygen demand of the water is therefore increased by 1.5 ton as this is the amount of Oxygen consumed by the ethanol.
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