Question

what is -1/2+1/3 , -3 1/5+(-6 1/2) , 5/8-(-2/8) , -9/10-2/5 , 6 3/5-(-2 1/5) answer all in sum or difference

Answer 1

Part a) $-\frac{1}{2} +\frac{1}{3}$

$-\frac{1}{2} +\frac{1}{3}=\frac{-3+2}{(3*2)} =-\frac{1}{6}$

the answer Part a) is

$-\frac{1}{6}$

Part b) $-3\frac{1}{5} +(-6\frac{1}{2} )$  

we know that

$-3\frac{1}{5}=-\frac{3*5+1}{5}=- \frac{16}{5}$

$-6\frac{1}{2}=-\frac{6*2+1}{2}=- \frac{13}{2}$

substitute

$- \frac{16}{5}-\frac{13}{2}=\frac{-32-65}{10} =-\frac{97}{10}$

therefore

the answer part b) is

$-\frac{97}{10}$

Part c) $\frac{5}{8}-(- \frac{2}{8})$

$\frac{5}{8}-(- \frac{2}{8})=\frac{5}{8}+ \frac{2}{8}=\frac{7}{8}$

therefore

the answer part c) is

$\frac{7}{8}$

Part d) $-\frac{9}{10}- \frac{2}{5}$

$-\frac{9}{10}- \frac{2}{5} =\frac{-9-4}{10}=- \frac{13}{10}$

therefore

the answer part d) is

$- \frac{13}{10}$

Part e) $6\frac{3}{5}-(2\frac{1}{5})$

we know that

$6\frac{3}{5}=\frac{6*5+3}{5}=\frac{33}{5}$

$2\frac{1}{5}=\frac{2*5+1}{5}=\frac{11}{5}$

substitute

$\frac{33}{5}-\frac{11}{5}=\frac{22}{5}$

therefore

the answer Part e) is

$\frac{22}{5}$

Answer 2

Answer:

Step-by-step explanation:

1. $\frac{-1}{2} + \frac{1}{3}$

We solve it by taking LCM (-3 + 2) / (3 x 6) = 1/6

2. $-3\frac{1}{5} + (-6\frac{1}{2} )$

By taking LCM:

-3 1/5 = (-3 x 5 + 1) / 5 = -16/5

-6 1/2 = - (6 x 2 +1) / 2 = -13/2

Subtracting these values:

-16/5 + (-13/2) = -97/10

3. $\frac{5}{8} - (-\frac{2}{8} )$

Adding the fraction to get: 5/8 + 2/8 = 7/8

4. $-\frac{9}{10} - \frac{2}{5}$

Taking the LCM:

(-9 - 4) / 10 = 13/10

5. $6\frac{3}{5} - (-2\frac{1}{5} )$

Taking the LCM to get:

33/5 + 11/5 = 22/5