Question

find the 6th term of geometric sequence whose common ratio is 3/2 and whose first term is 2

Answer 1

Answer:

243/16

Step-by-step explanation:

we have a1 = 2

r = 3/2

n = 6

Answer 2

The 6th term of the geometric sequence is 243/16

The given parameters are:

$a = 2$ --- the first term

$r = 3/2$ --- the common ratio

The nth term of a geometric sequence is:

$T_n = ar^{n-1$

So, the 6th term would be:

$T_6 = 2 \times (3/2)^{6-1$

Subtract 1 from 6

$T_6 = 2 \times (3/2)^5$

Evaluate the exponent

$T_6 = 2 \times (243/32)$

Simplify

$T_6 = 243/16$

Hence, the 6th term of the geometric sequence is 243/16

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