Answer:
[tex]\boxed { \sf (-2, -6) }}[/tex]
Step-by-step explanation:
We are asked to find the solution of the system of equations.
[tex]8x-3y=2\\-8x-5y=46[/tex]
When we solve systems of equations, we have to do 2 steps. The first step eliminates one variable so we can solve for the other. The next step helps us find the variable we canceled.
The first equation has the term 8x and the second equation has the term -8x. If these are added, they cancel, so we are left with the variable y. Add the equations together.
[tex](8x-3y=2) \\+ (-8x-5y=46)[/tex]
8x and -8x cancel, then add.
[tex](-3y=2)\\+ (-5y=46)[/tex]
___________
[tex]-8y= 48[/tex]
We are solving for y, so we must isolate the variable. It is being multiplied by -8. The inverse operation of multiplication is division. Divide both sides by -8.
[tex]-8y/-8=48/-8 \\y= 48/-8 \\y=-6[/tex]
Now we know what y is equal to, so we can plug it back into one of the original equations and solve for x.
I chose the first equation.
[tex]8x-3y=2[/tex]
[tex]8x-3(-6)=2[/tex]
[tex]8x+18=2[/tex]
Subtract 18 from both sides to isolate 8x.
[tex]8x+18-18=2-18\\8x=2-18\\8x=-16[/tex]
Divide both sides by 8.
[tex]8x/8=-16/8 \\x=-16/8 \\x= -2[/tex]
Coordinate points are written as (x,y) so our solution is (-2, -6)
